document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334699>Question 334699</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three times the complement of angle A is 40 degrees more than the supplement of angle A. Find the measure of angle A. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239882 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Three times the complement of angle A is 40 degrees more than the supplement of angle A. Find the measure of angle A.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let the angle be x<BR>\n" );
document.write( "complement = 90-x<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "....<BR>\n" );
document.write( "180-x = 3(90-x) +40<BR>\n" );
document.write( "180-x = 270-3x+40<BR>\n" );
document.write( "3x-x=270-180+40<BR>\n" );
document.write( "2x=130<BR>\n" );
document.write( "x= 130/2<BR>\n" );
document.write( "x= 65 deg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );