document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334768>Question 334768</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the hypotenuse of a isosceles right triangle measures 15feet.find the area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239875 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hypotenuse of isosceles right triangle = 15 feet<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let leg be x<BR>\n" );
document.write( "x^2+x^2=15^2<BR>\n" );
document.write( "2x^2=225<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x^2= 225/2<BR>\n" );
document.write( "x= sqrt(225/2)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area of triangle = 1/2 * leg1*leg2<BR>\n" );
document.write( "=1/2 *sqrt(225/2)*sqrt(225/2)<BR>\n" );
document.write( "=1/2 * 225/2<BR>\n" );
document.write( "= 225/2<BR>\n" );
document.write( "=112.5 sq.feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );