document.write( "Question 334716: Solve using the substitution method\r
\n" ); document.write( "\n" ); document.write( "\"4x%2B3y=7\"
\n" ); document.write( "\"2x-y=1\"\r
\n" ); document.write( "\n" ); document.write( "I could use some help on this on please.
\n" ); document.write( "thank you
\n" ); document.write( "

Algebra.Com's Answer #239838 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
\"4x%2B3y=7\"
\n" ); document.write( "\"2x-y=1\"
\n" ); document.write( "y=2x-1
\n" ); document.write( "replace y in the first equation by (2x-1) & solve for x.
\n" ); document.write( "4x+3(2x-1)=7
\n" ); document.write( "4x+6x-3=7
\n" ); document.write( "10x=7+3
\n" ); document.write( "10x=10
\n" ); document.write( "x=1 ans.
\n" ); document.write( "y=2*1-1
\n" ); document.write( "y=2-1
\n" ); document.write( "y=1 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "4*1+3*1=7
\n" ); document.write( "4+3=7
\n" ); document.write( "7=7
\n" ); document.write( "
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