document.write( "Question 334667: lois rode her bike to visit a friend. she traveled at 10 mi/h. while she was there it began to rain. her friend drove her home in a car traveling at a speed of 25 mi/h. lois took 1.5 h longer to go to her friends house than to return home. how many hours did it take lois to ride to her friends house? \n" ); document.write( "
Algebra.Com's Answer #239831 by ankor@dixie-net.com(22740)\"\" \"About 
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lois rode her bike to visit a friend. she traveled at 10 mi/h.
\n" ); document.write( " while she was there it began to rain. her friend drove her home in a car
\n" ); document.write( " traveling at a speed of 25 mi/h.
\n" ); document.write( " lois took 1.5 h longer to go to her friends house than to return home.
\n" ); document.write( " how many hours did it take lois to ride to her friends house?
\n" ); document.write( ":
\n" ); document.write( "let t = time to bike to friend's house
\n" ); document.write( "then
\n" ); document.write( "(t-1.5) = time to ride home
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "Dist to = return dist
\n" ); document.write( "10t = 25(t-1.5)
\n" ); document.write( "10t = 25t - 37.5
\n" ); document.write( "10t - 25t = -37.5
\n" ); document.write( "-15t = -37.5
\n" ); document.write( "t = \"%28-37.5%29%2F%28-15%29\"
\n" ); document.write( "t = +2.5 hrs to bike to friends house
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the distances, should be equal
\n" ); document.write( "10*2.5 = 25 mi
\n" ); document.write( "25(2.5-1.5) = 25 mi \n" ); document.write( "
\n" );