document.write( "Question 334674: A plane flying the 3020-mile trip from City A to City B has a 60 mph tailwind. The flights point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plane in still air is 430 mph, how far from City A is the point of no return? I need to translate the problem into a pair of linear equations in two variables.
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\n" ); document.write( "Ok, I have a line:
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\n" ); document.write( " 3020 miles
\n" ); document.write( "City A -------------------------------------------- City B
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\n" ); document.write( "I know d = rt
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\n" ); document.write( "and the distance is 3020 miles.
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\n" ); document.write( "So it is rt = 3020, but with the 60 mph tailwind and 430 mph and all that I am just confused.
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Algebra.Com's Answer #239824 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A plane flying the 3020-mile trip from City A to City B has a 60 mph tailwind. The flights point of no return is the point at which the flight time required to return to City A is the same as the time required to continue to City B. If the speed of the plane in still air is 430 mph, how far from City A is the point of no return? I need to translate the problem into a pair of linear equations in two variables.\r
\n" ); document.write( "\n" ); document.write( "Ok, I have a line:\r
\n" ); document.write( "\n" ); document.write( "3020 miles
\n" ); document.write( "City A -------------------------------------------- City B\r
\n" ); document.write( "\n" ); document.write( "I know d = rt
\n" ); document.write( "---
\n" ); document.write( "Note: The rates change from \"to\" to \"from\":
\n" ); document.write( "Let \"x\" miles from A be the point of no return,
\n" ); document.write( "then 3020-x is the remaining distance to B and
\n" ); document.write( "\"x\" is the distance back to A:
\n" ); document.write( "-----------
\n" ); document.write( "Equation:
\n" ); document.write( "time to complete the flight to B with wind = time to return to A against wind
\n" ); document.write( "(3020-x)/490 = x/370
\n" ); document.write( "370(3020-x) = 490x
\n" ); document.write( "370*3020-370x = 490x
\n" ); document.write( "370*3020 = 860x
\n" ); document.write( "x = 1299.3 miles from A
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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