document.write( "Question 334329: five times the complement of an angle less than twice the angles supplement is 30 degrees. Find the measure of the supplement. \n" ); document.write( "
Algebra.Com's Answer #239754 by ankor@dixie-net.com(22740)\"\" \"About 
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five times the complement of an angle less than twice the angles supplement is 30 degrees.
\n" ); document.write( "Find the measure of the supplement.
\n" ); document.write( ":
\n" ); document.write( "let a = \"an angle\"
\n" ); document.write( "we know
\n" ); document.write( "(90-a) = it's complement
\n" ); document.write( "and
\n" ); document.write( "180-a) = it's supplement
\n" ); document.write( ":
\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "\"five times the complement of an angle less than twice the angles supplement is 30 degrees. \"
\n" ); document.write( "5(90-a) - 2(180-a) = 30
\n" ); document.write( "450 - 5a - 360 + 2a = 30
\n" ); document.write( "-5a + 2a + 450 - 360 = 30
\n" ); document.write( "-3a + 90 = 30
\n" ); document.write( "-3a = 30 - 90
\n" ); document.write( "-3a = -60
\n" ); document.write( "a = \"%28-60%29%2F%28-3%29\"
\n" ); document.write( "a = +20 degrees is the angle
\n" ); document.write( "but it says:
\n" ); document.write( "\"Find the measure of it's supplement\"
\n" ); document.write( "180 - 20 = 160 degrees
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this in the statement:
\n" ); document.write( "five times the complement of an angle less than twice the angles supplement is 30 degrees.
\n" ); document.write( "5(90-20) - 2(160) = 30
\n" ); document.write( "350 - 320 = 30; confirms our solutions
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