document.write( "Question 334497: Kyle's lock combination consists of 3 two-digit numbers. The combination satisfies the three conditions below. \r
\n" ); document.write( "\n" ); document.write( "One number is odd.
\n" ); document.write( "One number is a multiple of 5.
\n" ); document.write( "One number is the day of the month of Kyle's birthday. \r
\n" ); document.write( "\n" ); document.write( "If each number satisfies exactly one of the conditions, which of the following could be the combination to the lock?\r
\n" ); document.write( "\n" ); document.write( "(A) 14-20-13
\n" ); document.write( "(B) 14-25-13
\n" ); document.write( "(C) 15-18-16
\n" ); document.write( "(D) 20-15-20
\n" ); document.write( "(E) 34-30-21
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Algebra.Com's Answer #239680 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
3 number combination such that
\n" ); document.write( "One number is odd.
\n" ); document.write( "One number is a multiple of 5.
\n" ); document.write( "One number is the day of the month of Kyle's birthday.
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\n" ); document.write( "Process of elimination
\n" ); document.write( "eliminate choice B, since it has two odd numbers
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\n" ); document.write( "multiples of 5, end in 5 or 0, but since one number has to be odd while another a multiple of 5, that means only those ending in 0 qualify, therefore, eliminate choice C
\n" ); document.write( "also eliminate choice D, since there would be two multiples of 5
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\n" ); document.write( "that leave choice A and E, but since the third critiria states that it has to be a day of the month, eliminate choice E since 34 is too high for a day of the month
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\n" ); document.write( "Answer: choice A
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