document.write( "Question 38477: A man paid the bank $4,080 at the end of 3 years. This was the amount borrowed plus 12% interest for 3 years. How much money had he borrowed? \n" ); document.write( "
Algebra.Com's Answer #23967 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
\"Use+the+formula+A=Pe%5E%28rt%29\"
\n" ); document.write( "\"A=4080e%5E%280.12%2A3%29\"
\n" ); document.write( "\"A=4080e%5E0.36\"
\n" ); document.write( "A=5847.98
\n" ); document.write( "Hence, he borrowed $5847.98
\n" ); document.write( "PAul.
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