document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334477>Question 334477</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 7 inches longer than the base and 14 inches longer than the height. The perimeter of the triangle is 84 inches. Find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239655 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let hypotenuse be x<BR>\n" );
document.write( "side 1 = x-7<BR>\n" );
document.write( "side 2 = x-14<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+x-7+x-14=84<BR>\n" );
document.write( "3x-21=84<BR>\n" );
document.write( "add 21<BR>\n" );
document.write( "3x-21+21=84+21<BR>\n" );
document.write( "3x=105<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "x= 35<BR>\n" );
document.write( "..<BR>\n" );
document.write( "base = 35-7= 28<BR>\n" );
document.write( "height = 35-14= 21<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Area = 1/2 * 21*28<BR>\n" );
document.write( "=21*14<BR>\n" );
document.write( "=294 sq. inches </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );