document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38448>Question 38448</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ASSUME THAT LOG 4=0.6021, LOG 5=0.699 AND LOG 6=0.7782 USE THE PRPETIES OF LOGARITHMS TO EVALUATE EACH EXPRESSION ROUNF YOUR ANSWER TO THE NEAREST THOUSANDTH\r<BR>\n" );
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document.write( "1.) log 0.8\r<BR>\n" );
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document.write( "2.) log 30 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23961 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log .8 = log 4/5 = log 4 - log 5 = .6021 - .699 = -.0969 or about -.097<BR>\n" );
document.write( "log 30 = log 6*5 = log 6 + log 5 = .7782 + .699 = 1.4772 or about 1.477 </SPAN>\n" );
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