document.write( "Question 334413: In the vicinity of a bonfire, the temperature T in degree celsius at a distance of x meters from the center of the fire was given by:\r
\n" ); document.write( "\n" ); document.write( "T=600000/(x^2+300)\r
\n" ); document.write( "\n" ); document.write( "At what range of distances from the fire's center was the temperature less than 500 degree celsius?
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Algebra.Com's Answer #239595 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
\"T=600000%2F%28x%5E2%2B300%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B300+=+600000%2FT\"
\n" ); document.write( "\"x%5E2+=+%28600000%2FT%29+-+300\"
\n" ); document.write( "\"x+=+sqrt%28%28600000%2FT%29+-+300%29\"\r
\n" ); document.write( "\n" ); document.write( "What distance is the temperature 500?
\n" ); document.write( "\"x+=+sqrt%28%28600000%2F500%29+-+300%29\"
\n" ); document.write( "\"x+=+sqrt%281200+-+300%29\"
\n" ); document.write( "\"x+=+sqrt%28900%29\"
\n" ); document.write( "\"x+=+30\"
\n" ); document.write( "So at 30 meters the temperature is 500.
\n" ); document.write( "Any distance greater than 30m will result in a temperature less than 500\r
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