document.write( "Question 334363: 2X-5Y=10
\n" ); document.write( "3X+4Y=15
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Algebra.Com's Answer #239594 by privani(34)\"\" \"About 
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2X-5Y=10 .... (1)
\n" ); document.write( "3X+4Y=15 .... (2)
\n" ); document.write( "------------ (1)*4 and (2)*5
\n" ); document.write( "8X -20Y=40 ...(3)
\n" ); document.write( "15X+20Y=75 ...(4)
\n" ); document.write( "------------ (3)+(4)
\n" ); document.write( "20X = 115
\n" ); document.write( "X = 115/20
\n" ); document.write( "X = 23/4 ....(5)\r
\n" ); document.write( "\n" ); document.write( "Substitute (5) in (1)
\n" ); document.write( "2X-5Y=10
\n" ); document.write( "\"2%2823%2F4%29-5Y=10\"
\n" ); document.write( "\"%2823%2F2%29-5Y=10\"
\n" ); document.write( "\"-5Y=10-23%2F2\"
\n" ); document.write( "\"-5Y=%2820-23%29%2F2\"
\n" ); document.write( "\"Y=%28-3%2F2%29%2F-5\"
\n" ); document.write( "\"Y=%28-3%2F2%29%2A%28-1%2F5%29\"
\n" ); document.write( "\"Y=3%2F10\"
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