document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334400>Question 334400</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, one angle is 6 degrees more than the second angle.  The third angle is 18 degrees  more than the second angle.  Find the measure of each angle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239588 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239588\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let second angle be x<BR>\n" );
document.write( "the first angle will be x+6<BR>\n" );
document.write( "the third angle = x+6+18<BR>\n" );
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document.write( "Their sum =180 deg<BR>\n" );
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document.write( "x+x+6+x+6+18=180<BR>\n" );
document.write( "3x+30 =180<BR>\n" );
document.write( "add -30<BR>\n" );
document.write( "3x+30-30 = 180-30<BR>\n" );
document.write( "3x=150<BR>\n" );
document.write( "divide by 3<BR>\n" );
document.write( "x= 50 deg<BR>\n" );
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document.write( "First angle = 50+6= 56 deg<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Third angle = x+24= 50+6+18<BR>\n" );
document.write( "=74<BR>\n" );
document.write( "..<BR>\n" );
document.write( "CHECK <BR>\n" );
document.write( "50+56+74= 180 </SPAN>\n" );
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