document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334342>Question 334342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 9 feet less than twice its width. The perimeter is 54 feet. What are the width and length of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239549 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 9 feet less than twice its width. The perimeter is 54 feet. What are the width and length of the rectangle?<BR>\n" );
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document.write( "Let width = W<BR>\n" );
document.write( "Then length = L = 2W-9<BR>\n" );
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document.write( "Perimeter = 2(L+W)<BR>\n" );
document.write( "54 = 2(2W-9+W)<BR>\n" );
document.write( "27 = 3W-9<BR>\n" );
document.write( "3W = 36<BR>\n" );
document.write( "W = 12 ft (width)<BR>\n" );
document.write( "L = 2W-9 = 15 ft (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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