document.write( "Question 334336: How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to obtain a 75% acid solution? \n" ); document.write( "
Algebra.Com's Answer #239548 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to obtain a 75% acid solution? \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.50*40 + x = 0.75(40+x) \n" ); document.write( "------- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50*40 + 100x = 75*40 + 75x \n" ); document.write( "25x = 25*40 \n" ); document.write( "x = 40 milliters (amt. of pure HCL needed for the mixture) \n" ); document.write( "=============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |