document.write( "Question 334336: How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to obtain a 75% acid solution? \n" ); document.write( "
Algebra.Com's Answer #239548 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How much pure hydrocloric acid must be added to 40 milliliters of a 50% solution to obtain a 75% acid solution?
\n" ); document.write( "-----
\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.50*40 + x = 0.75(40+x)
\n" ); document.write( "-------
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "50*40 + 100x = 75*40 + 75x
\n" ); document.write( "25x = 25*40
\n" ); document.write( "x = 40 milliters (amt. of pure HCL needed for the mixture)
\n" ); document.write( "===============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===========
\n" ); document.write( "
\n" );