document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38362>Question 38362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help.<BR>\n" );
document.write( "Subtract and write answer in simplest form.\r<BR>\n" );
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document.write( "y-2/y+3 - y/2y+6\r<BR>\n" );
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document.write( "I am getting y-4/2(y+3)\r<BR>\n" );
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document.write( "Is this right? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23951 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From<BR>\n" );
document.write( "y-2/y+3 - y/2y+6, we can multiply the first fractaion by 2/2 in order to combine it with the second fraction...so we get<BR>\n" );
document.write( "y-2/y+3 - y/2y+6 =<BR>\n" );
document.write( "(2y - 4) / (2y + 6) - y / (2y + 6) =<BR>\n" );
document.write( "(y - 4) / (2y + 6) or<BR>\n" );
document.write( "(y - 4) / 2(y + 3)<BR>\n" );
document.write( "Looks like what you got!  Way to go! </SPAN>\n" );
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