document.write( "Question 334246: How do you solve for r in this equation:((2r+5)/5)-((3r+1)/2)=((7-r)/2) \n" ); document.write( "

Algebra.Com's Answer #239499 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28%282r%2B5%29%2F5%29-%28%283r%2B1%29%2F2%29=%28%287-r%29%2F2%29\"$
\n" ); document.write( "Multiply by 10 to get rid of the denominators; results:
\n" ); document.write( "2(2r+5) - 5(3r+1) = 5(7-r)
\n" ); document.write( ":
\n" ); document.write( "4r + 10 - 15r - 5 = 35 - 5r
\n" ); document.write( "Combine the r's on the left, numbers on the right
\n" ); document.write( "4r - 15r + 5r = 35 - 10 + 5
\n" ); document.write( ":
\n" ); document.write( "-6r = 30
\n" ); document.write( "r = $\"30%2F%28-6%29\"$
\n" ); document.write( "r = -5
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check solution in original equation
\n" ); document.write( " $\"%28%282%28-5%29%2B5%29%2F5%29-%28%283%28-5%29%2B1%29%2F2%29=%28%287-%28-5%29%29%2F2%29\"$
\n" ); document.write( " $\"%28%28-10%2B5%29%2F5%29-%28%28-15%2B1%29%2F2%29=%28%287%2B5%29%2F2%29\"$
\n" ); document.write( " $\"%28-5%29%2F5\"$ - $\"%28-14%29%2F2\"$ = $\"12%2F2\"$
\n" ); document.write( "-1 + 7 = 6 \n" ); document.write( "

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