document.write( "Question 334172: A man drove the first 75 miles of a trip at an average of 50mph. He then drove the next 150 miles at an average of 60 mph. What was his average speed in mph for the trip? \n" ); document.write( "
Algebra.Com's Answer #239468 by ankor@dixie-net.com(22740)\"\" \"About 
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A man drove the first 75 miles of a trip at an average of 50mph.
\n" ); document.write( " He then drove the next 150 miles at an average of 60 mph.
\n" ); document.write( " What was his average speed in mph for the trip?
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\n" ); document.write( "Let a = average speed for the trip
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\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( "Total trip dist = 75 + 150 = 225
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\n" ); document.write( "50mph time + 60mph time = total time
\n" ); document.write( "\"75%2F50\" + \"150%2F60\" = \"225%2Fa\"
\n" ); document.write( ":
\n" ); document.write( "Multiply by 300a to get rid of the denominators, results
\n" ); document.write( "6a(75) + 5a(150) = 300(225)
\n" ); document.write( ":
\n" ); document.write( "450a + 750a = 67500
\n" ); document.write( ":
\n" ); document.write( "1200a = 67500
\n" ); document.write( "a = \"67500%2F1200\"
\n" ); document.write( "a = 56.25 mph is the average speed
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\n" ); document.write( "See if that is true, find the times:
\n" ); document.write( "\"75%2F50\" + \"150%2F60\" = \"225%2F56.25\"
\n" ); document.write( "1.5 + 2.5 = 4
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