document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334198>Question 334198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello!\r<BR>\n" );
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document.write( "This one has been giving me a hard time and couldn't figure it out. Any help is greatly appreciated. Thank you in advance...\r<BR>\n" );
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document.write( "Solve the problem:\r<BR>\n" );
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document.write( "The current, in ampheres, for a piece of wire with an electromotive force of 88 volts, is given by the function C(r)=88/r, where r is the resistance of the wire in ohms. What is the current, rounded to the nearest hundredth of an ampere, if the wire has a resistance of 15 ohms?\r<BR>\n" );
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document.write( "Thank you!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239465 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239465\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I is used for amperes.<BR>\n" );
document.write( "I = 88/r = 88/15<BR>\n" );
document.write( "I =~ 5.87 amps<BR>\n" );
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