document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38425>Question 38425</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to help my son, and I forgot the rules!!!\r<BR>\n" );
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document.write( "75=-5a/3\r<BR>\n" );
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document.write( "Thanks!!<BR>\n" );
document.write( "mom </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23946 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, Mom, I have five kids, I can dig it...<BR>\n" );
document.write( "From 75 = -5a/3, let us multiply both sides by -3/5 (the reciprocal) and get<BR>\n" );
document.write( "(-3/5)(75) = (-3/5)(-5a/3)<BR>\n" );
document.write( "That way the fractions on the right cancel out, leaving only a.  Thus<BR>\n" );
document.write( "a = (-3/5)(75) = -45 </SPAN>\n" );
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