document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334167>Question 334167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a right triangle has a hypotenuse with length 15cm. If one of the acute angles of the triangle is 25degrees, find the length of the two shorter sides of the triangle correct to the nearest tenth of a centimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239455 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if you have a right triangle and one of the acute angles is 25 degrees<BR>\n" );
document.write( "then use trig functions to find the other legs.\r<BR>\n" );
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document.write( "Sin(25) = Opposite leg/hypotenuse, and cos(25)=adjacent leg/hypotenuse<BR>\n" );
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document.write( "So......<BR>\n" );
document.write( "Opposite leg = hypotenuse*Sin(25)   and adjacent leg = hypotenuse*cos(25)<BR>\n" );
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document.write( "opposite leg = 15*sin(25) = 15*(0.4226)=6.3; <BR>\n" );
document.write( "adjacent leg = 15*cos(25) =15*(0.906)=13.6\r<BR>\n" );
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document.write( "===\r<BR>\n" );
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document.write( "check<BR>\n" );
document.write( "in a right triangle, leg1^2+leg2^2=hypotenuse^2<BR>\n" );
document.write( "6.3^2+13.6^2 = 39.7+185.0=224.7;    15^2=225  so it checks out </SPAN>\n" );
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