document.write( "Question 334154: The ages (in years) of the employees at a particular computer store are \r
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document.write( " 36,40,24,24,31\r
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document.write( "Assuming that these ages constitute an entire population, find the standard deviation of the population. Round your answer to at least two decimal places.\r
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Algebra.Com's Answer #239445 by jrfrunner(365) You can put this solution on YOUR website! 1. compute the average: add the values and divide by 5 \n" ); document.write( "Average =(36+ 40+24+24+31)/5=31.0 \n" ); document.write( "-- \n" ); document.write( "2. Compute the deviations from the average \n" ); document.write( "dev: (36-31)=5, (40-31)=9,etc \n" ); document.write( "-- \n" ); document.write( "3. Square the deviations and add \n" ); document.write( "sum (dev^2): 5^2+9^+...+0^2=204 \n" ); document.write( "-- \n" ); document.write( "4. Divide step #3 by the sample size=5 (typically you divide by sample size-1 to get the sample standard deviation, but you are assuming the 5 values are the population, so no need to subtract 1, from the sample size. This result is the variance \n" ); document.write( "Variance =204/5=40.8 \n" ); document.write( "-- \n" ); document.write( "5. Standard deviation = sqrt(variance) \n" ); document.write( "standard deviation= sqrt(40.8) \n" ); document.write( " |