document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334103>Question 334103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular room is 1and 2/3 ft more than its width and its perimeter is 46ft.<BR>\n" );
document.write( "Find the length and width of the room.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239390 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239390\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x ft<BR>\n" );
document.write( "length will be x+5/3 ft.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Perimeter = 2L +2W<BR>\n" );
document.write( "=2x+2(x+5/3)<BR>\n" );
document.write( "=2x+2x+10/3<BR>\n" );
document.write( "=4x+(10/3) =46<BR>\n" );
document.write( "=12x+10 /3 = 46<BR>\n" );
document.write( "12x +10 =138<BR>\n" );
document.write( "12x= 138-10<BR>\n" );
document.write( "12x=128<BR>\n" );
document.write( "x= 10.66 feet width <BR>\n" );
document.write( "length = 10.66+1.75 = 12.41 feet<BR>\n" );
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