document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334097>Question 334097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> dad is seven times as old as his son. 10 years later, he will be three times as old as his son. find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239362 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let son be x years<BR>\n" );
document.write( "dad = 7x<BR>\n" );
document.write( "..\r<BR>\n" );
document.write( "\n" );
document.write( "10 years later<BR>\n" );
document.write( "son = x+10 years<BR>\n" );
document.write( "dad = 7x +10 years<BR>\n" );
document.write( "..<BR>\n" );
document.write( "7x+10=3(x+10)<BR>\n" );
document.write( "7x+10=3x+30<BR>\n" );
document.write( "7x-3x=30-10<BR>\n" );
document.write( "4x = 20<BR>\n" );
document.write( "x= 5<BR>\n" );
document.write( "son's age now = 5 years<BR>\n" );
document.write( "dad's age now = 7*5 = 35 years<BR>\n" );
document.write( "..\r<BR>\n" );
document.write( "\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );