document.write( "Question 334034: the width of a box is 2 feet less than the length, the height is 8 feet greater than the length. The box has a cubic volume of 96 cubic feet. What are the dimensions of the box? \n" ); document.write( "
Algebra.Com's Answer #239330 by mananth(16946)\"\" \"About 
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the width of a box is 2 feet less than the length, the height is 8 feet greater than the length. The box has a cubic volume of 96 cubic feet. What are the dimensions of the box?
\n" ); document.write( "let length be x
\n" ); document.write( "width = x-2
\n" ); document.write( "height = x+8
\n" ); document.write( "..
\n" ); document.write( "volume = 96 cu.ft.
\n" ); document.write( "..
\n" ); document.write( "x(x-2)(x+8)= 96
\n" ); document.write( "x(x^2+6x-16)=96
\n" ); document.write( "x^3+6x^2-16x=96
\n" ); document.write( "x^3+6x^2-16x-96=0
\n" ); document.write( "x^2(x+6)-16(x+6)=0
\n" ); document.write( "(x+6)(x^2-16)=0
\n" ); document.write( "(x+6)(x-4)(x+4)=0
\n" ); document.write( "ignoring the negative value of x
\n" ); document.write( "x= 4 the length
\n" ); document.write( "width = 2
\n" ); document.write( "height = 12\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "4*2*12 = 96 cu.ft\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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