document.write( "Question 333984: Karen notices that her husband left for the airport without his briefcase. Her husband drives 40 miles per hour and has a 15 minute head start. If Karen (with the briefcase) drives 60 miles per hour and the airport is 45 miles away, will she catch him before he arrives at the airport? \n" ); document.write( "
Algebra.Com's Answer #239313 by ankor@dixie-net.com(22740)\"\" \"About 
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Karen notices that her husband left for the airport without his briefcase.
\n" ); document.write( " Her husband drives 40 miles per hour and has a 15 minute head start.
\n" ); document.write( " If Karen (with the briefcase) drives 60 miles per hour and the airport is 45 miles away,
\n" ); document.write( " will she catch him before he arrives at the airport?
\n" ); document.write( ":
\n" ); document.write( "Find out how long it will take to catch him
\n" ); document.write( "Change 15 min to .25 hrs
\n" ); document.write( ":
\n" ); document.write( "t = K's travel time
\n" ); document.write( "then
\n" ); document.write( "(t+.25) = hus travel time
\n" ); document.write( ":
\n" ); document.write( "When K catches h, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( "60t = 40(t+.25)
\n" ); document.write( "60t = 40t + 10
\n" ); document.write( "60t - 40t = 10
\n" ); document.write( "20t = 10
\n" ); document.write( "t = \"10%2F20\"
\n" ); document.write( "t = .5 hr for K to catch h
\n" ); document.write( ":
\n" ); document.write( "Find the distance
\n" ); document.write( "60*.5 = 30 mi, well before the airport which is 45 mi
\n" ); document.write( ":
\n" ); document.write( "Confirm solution by finding the dist h travels
\n" ); document.write( "40 *(.5+.25) = 30mi also \n" ); document.write( "
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