document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333964>Question 333964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 110 inches  the length is 10m more than twice the width find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239301 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W<BR>\n" );
document.write( "L=2W+10 <BR>\n" );
document.write( "REPLACE L WITH (2W+10) IN THE PERIMEYTER EQUATION & SOLVE FOR W<BR>\n" );
document.write( "110=2(2W+10)+2W<BR>\n" );
document.write( "110=4W+20+2W<BR>\n" );
document.write( "110=6W+20<BR>\n" );
document.write( "6W=110-20<BR>\n" );
document.write( "6W=90<BR>\n" );
document.write( "W=90/6<BR>\n" );
document.write( "W=15 ANS. FOR THE WIDTH. <BR>\n" );
document.write( "L=2*15+10<BR>\n" );
document.write( "L=30+10=40 ANS FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "110=2*40+2*15<BR>\n" );
document.write( "110=80+30<BR>\n" );
document.write( "110=110 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );