document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4847>Question 4847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tyrone is twice as old as his daughter. In six years Tyrone's age will be three times what his daughters age was six years ago. How old are they at present? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2393 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t = age now of Tyrone<BR>\n" );
document.write( "Let d = age now of daughter\r<BR>\n" );
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document.write( "t = 2d --eqn1\r<BR>\n" );
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document.write( "Second piece of info is (t+6) = 3(d-6) --eqn2\r<BR>\n" );
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document.write( "eqn2 becomes t+6 = 3d-18. Sub into it, eqn1, to get 2d+6 = 3d-18.<BR>\n" );
document.write( "2d+6 = 3d-18<BR>\n" );
document.write( "+6 = d-18<BR>\n" );
document.write( "d-18 = 6<BR>\n" );
document.write( "d = 24\r<BR>\n" );
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document.write( "and from eqn1, t=2x24 --> t=48\r<BR>\n" );
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document.write( "jon.<BR>\n" );
document.write( " </SPAN>\n" );
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