document.write( "Question 333906: 1/3x + 3 = 3/4y \n" ); document.write( "
Algebra.Com's Answer #239273 by checkley77(12844)\"\" \"About 
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1/3x + 3 = 3/4y
\n" ); document.write( "3y/4=x/3+3 divide by 3/4
\n" ); document.write( "y=(x/3)/(3/4)+3/(3/4) invert the denominators & multiply.
\n" ); document.write( "y=x/3*4/3+3*4/3 multiply numerators & denominators & reduce.
\n" ); document.write( "y=4x/9+12/3
\n" ); document.write( "y=4x/9+4 ans.
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