document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38417>Question 38417</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the measurement of height if the radius of the cylinder is 3cm and the volume is 121cm?  Then graph this function.\r<BR>\n" );
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document.write( "This is what I got so far:<BR>\n" );
document.write( "v=2pir^2 + 2pirh<BR>\n" );
document.write( "121= 2pe(3)^2 + 2pi(3)h<BR>\n" );
document.write( "121 = 18 + 6<BR>\n" );
document.write( "h= 24\r<BR>\n" );
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document.write( "I don't know if this is right.  Don't I need 2 points to plot anything on a graph?  Could you please help me?  Christine </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #23921 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=23921\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of a right circular cylinder is found by<BR>\n" );
document.write( "V = (pi)(r^2)h<BR>\n" );
document.write( "If the radius is 3 and the volume is 121, we have<BR>\n" );
document.write( "121 = (pi)(9)h and<BR>\n" );
document.write( "h = 121 / 9(pi) </SPAN>\n" );
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