document.write( "Question 333851: a chem lab keeps 2 acids solutions on hand. one is 20% acid and the other is 35% acid. How much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% acid solution? \n" ); document.write( "

Algebra.Com's Answer #239209 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
a chem lab keeps 2 acids solutions on hand. one is 20% acid and the other is 35% acid. How much 20% and how much 35% acid solution should be used to prepare 25 liters of a 26% acid solution?
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity Eq.: x + y = 25
\n" ); document.write( "Acid Eq::::0.20x + 0.35y = 0.26*25
\n" ); document.write( "------
\n" ); document.write( "Multiply thru the Quantity Eq. by 20
\n" ); document.write( "Multiply thru the Acid Eq by 100
\n" ); document.write( "----------------
\n" ); document.write( "20x + 20y = 20*25
\n" ); document.write( "20x + 35y = 26*25
\n" ); document.write( "----
\n" ); document.write( "Subtract 1st from 2nd to get:
\n" ); document.write( "15y = 6*25
\n" ); document.write( "y = 10 liters (amt. of 35% solution in the mixture.
\n" ); document.write( "-----
\n" ); document.write( "x = 25-y = 15 liters (amt. 20% solution in the mixture.
\n" ); document.write( "========================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

\n" );