document.write( "Question 333745: My algebra teacher gave us this problem, I don't know how to start solving it. Please help me.
\n" ); document.write( "Marty is 1/3 as old as her mother. Five years ago she was only 1/5 of the age of her mother. How old is Marty?
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Algebra.Com's Answer #239162 by ankor@dixie-net.com(22740)\"\" \"About 
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Let m = mother's present age
\n" ); document.write( "Let d = daughter's present age (Marty)
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "Marty is 1/3 as old as her mother.
\n" ); document.write( "d = \"1%2F3\"m
\n" ); document.write( "or we can say
\n" ); document.write( "m = 3d
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\n" ); document.write( "Five years ago she was only 1/5 of the age of her mother.
\n" ); document.write( "d - 5 = \"1%2F5\"(m-5)
\n" ); document.write( "Mult both sides by 5, get rid of that fraction
\n" ); document.write( "5(d-5) = m - 5
\n" ); document.write( "5d - 25 = m - 5
\n" ); document.write( "5d = m - 5 + 25
\n" ); document.write( "5d = m + 20
\n" ); document.write( "Replace m with 3d
\n" ); document.write( "5d = 3d + 20
\n" ); document.write( "5d - 3d = 20
\n" ); document.write( "2d = 20
\n" ); document.write( "d = 10 yrs is Marty
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\n" ); document.write( "check solution in the statement; m = 3(10) = 30 is mom
\n" ); document.write( "\"Five years ago she was only 1/5 of the age of her mother.
\n" ); document.write( "10 - 5 = \"1%2F5\"(30 - 5)\r
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