document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333701>Question 333701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the choice below which gives a first step in solving the given system of equations by the addition method. <BR>\n" );
document.write( "2x - 3y = 7<BR>\n" );
document.write( "x - 4y = 2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239109 by </B><A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><B>Edwin McCravy(20056)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Edwin+McCravy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Edwin+McCravy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Multiplying the second equation by -2. <i><font size = 1>[That's to make the x in the<BR>\n" );
document.write( "second equation become a -2x so that when you you add the two equations,<BR>\n" );
document.write( "like term by like term, you will be adding a 2x and a -2x which will give<BR>\n" );
document.write( "0, or as you might say, \"the x-terms will cancel out\".]</i></font>\r<BR>\n" );
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