document.write( "Question 333703: What is the answer to the system of equation below?\r
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\n" ); document.write( "3x+6y=6
\n" ); document.write( "x-2z=8
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Algebra.Com's Answer #239107 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
\"system%282x%2B3z=2%2C%0D%0A3x%2B6y=6%2C%0D%0Ax-2z=8%29\"
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document.write( "The first and third equations are in x and z only, \r\n" );
document.write( "that is, neither has a y terms, so we start by taking them\r\n" );
document.write( "as a system of 2 equations in 2 unknowns.\r\n" );
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document.write( "\"system%282x%2B3z=2%2C%0D%0Ax-2z=8%29\" \r\n" );
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document.write( "Multiply the second equation through by -2:\r\n" );
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document.write( "\"system%282x%2B3z=2%2C%0D%0A-2x%2B4z=-16%29\" \r\n" );
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document.write( "We get \r\n" );
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document.write( "\"7z=-14\" or\r\n" );
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document.write( "\"z=-2\"\r\n" );
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document.write( "Substituting in \r\n" );
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document.write( "\"x-2z=8\"\r\n" );
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document.write( "\"x-2%28-2%29=8\"\r\n" );
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document.write( "\"x%2B4=8\"\r\n" );
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document.write( "\"x=4\"\r\n" );
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document.write( "Substitute that in the original equation which contained y:\r\n" );
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document.write( "\"3x%2B6y=6\"\r\n" );
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document.write( "\"3%284%29%2B6y=6\"\r\n" );
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document.write( "\"12%2B6y=6\"\r\n" );
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document.write( "\"6y=-6\"\r\n" );
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document.write( "\"y=-1\"\r\n" );
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document.write( "So the solution is (x,y,z,) = (4,-1,-2)\r\n" );
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document.write( "Edwin
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