document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4880>Question 4880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2391 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let length = x<BR>\n" );
document.write( "Length width = y\r<BR>\n" );
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document.write( "we know that x+x+y+y=160 --> 2x+2y=160\r<BR>\n" );
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document.write( "Also, x/4 = 2y --> x = 8y.\r<BR>\n" );
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document.write( "Put this second equation into the first, to give 2(8y) + 2y = 160<BR>\n" );
document.write( "16y+2y = 160<BR>\n" );
document.write( "18y = 160<BR>\n" );
document.write( "y = 80/9<BR>\n" );
document.write( "y = 8.89 ft (to 2dp)\r<BR>\n" );
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document.write( "--> as x = 8y, we get x = 71.11 (to 2dp)\r<BR>\n" );
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document.write( "Check: add 2 lots of each length --> do you get 160?\r<BR>\n" );
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document.write( "jon\r<BR>\n" );
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document.write( " </SPAN>\n" );
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