document.write( "Question 333659: Any help is appreciated!\r
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document.write( "The speed of a passenger train is 8 mph faster than the speed of a freight train. The passenger train travels 270 miles in the same time it takes the freight to travel 230 miles. Find the speed of each train. \n" );
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Algebra.Com's Answer #239099 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The speed of a passenger train is 8 mph faster than the speed of a freight train. \n" ); document.write( " The passenger train travels 270 miles in the same time it takes the freight to travel 230 miles. \n" ); document.write( " Find the speed of each train. \n" ); document.write( ": \n" ); document.write( "Let s = speed of the freight train \n" ); document.write( "then \n" ); document.write( "(s+8) = speed of the pass train \n" ); document.write( ": \n" ); document.write( "Write a time equation, Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Pass time = Freight time \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "270s = 230(s+8) \n" ); document.write( "270s = 230s + 1840 \n" ); document.write( "270s - 230s = 1840 \n" ); document.write( "40s = 1840 \n" ); document.write( "s = \n" ); document.write( "s = 46 mph is the freight \n" ); document.write( "then \n" ); document.write( "46 + 8 = 54 mph is the pass \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm the solution, find the times, they should be equal \n" ); document.write( "270/54 = 5 hrs \n" ); document.write( "230/46 = 5 hrs also \n" ); document.write( " |