document.write( "Question 333670: The speedboat traveled at a speed that was twice as fast as the yacht. The speedboat traveled 240 miles in one hour less than it took the yacht to travel 150 miles. What were the speed and time for both the speedboat and the yacht? \n" ); document.write( "
Algebra.Com's Answer #239096 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The speedboat traveled at a speed that was twice as fast as the yacht. \n" ); document.write( " The speedboat traveled 240 miles in one hour less than it took the yacht to travel 150 miles. \n" ); document.write( " What were the speed and time for both the speedboat and the yacht? \n" ); document.write( ": \n" ); document.write( "let s = the speed of the yacht \n" ); document.write( "then \n" ); document.write( "2s = the speed of the speedboat \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "yacht time - speedboat time = 1 hr \n" ); document.write( " \n" ); document.write( "Multiply by 2s, clears the denominators \n" ); document.write( "2(150) - 240 = 2s \n" ); document.write( ": \n" ); document.write( "300 - 240 = 2s \n" ); document.write( ": \n" ); document.write( "60 = 2s \n" ); document.write( "s = \n" ); document.write( "s = 30 mph is the yacht \n" ); document.write( "then \n" ); document.write( "2(30) = 60 mph is the speedboat \n" ); document.write( ": \n" ); document.write( "Find the times \n" ); document.write( "150/30 = 5 hrs for yacht \n" ); document.write( "240/60 = 4 hrs for speedboat \n" ); document.write( "---------------------------- \n" ); document.write( "differ: 1 hr, confirms our solutions \n" ); document.write( " |