document.write( "Question 333674: Sixteen liters of an ideal gas at a temperature of 500 kelvins has a pressure of 100 newtons per square meter. If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure? \n" ); document.write( "
Algebra.Com's Answer #239095 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Sixteen liters of an ideal gas at a temperature of 500 kelvins has a pressure of 100 newtons per square meter.
\n" ); document.write( "---
\n" ); document.write( "Volume = k[t/p]
\n" ); document.write( "---
\n" ); document.write( "Find \"k\":
\n" ); document.write( "16 = k[500/100]
\n" ); document.write( "---
\n" ); document.write( "k = 16/5
\n" ); document.write( "----
\n" ); document.write( "Equation:
\n" ); document.write( "V = (16/5)[t/p]
\n" ); document.write( "---
\n" ); document.write( "If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure?
\n" ); document.write( "20 = (16/5)[400/p]
\n" ); document.write( "pressure = (16/5)[500/20]
\n" ); document.write( "---
\n" ); document.write( "Pressure = 16 neutons per sq. meter
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" ); document.write( "
\n" );