document.write( "Question 333674: Sixteen liters of an ideal gas at a temperature of 500 kelvins has a pressure of 100 newtons per square meter. If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure? \n" ); document.write( "
Algebra.Com's Answer #239095 by stanbon(75887) ![]() You can put this solution on YOUR website! Sixteen liters of an ideal gas at a temperature of 500 kelvins has a pressure of 100 newtons per square meter. \n" ); document.write( "--- \n" ); document.write( "Volume = k[t/p] \n" ); document.write( "--- \n" ); document.write( "Find \"k\": \n" ); document.write( "16 = k[500/100] \n" ); document.write( "--- \n" ); document.write( "k = 16/5 \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "V = (16/5)[t/p] \n" ); document.write( "--- \n" ); document.write( "If the volume were increased to 20 liters and the temperature reduced to 400 kelvins, what would be the pressure? \n" ); document.write( "20 = (16/5)[400/p] \n" ); document.write( "pressure = (16/5)[500/20] \n" ); document.write( "--- \n" ); document.write( "Pressure = 16 neutons per sq. meter \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |