document.write( "Question 333638: The general expression for consecutive multiples of seven is 7N, 7(N+1), 7(N+2), etc. Find three consecutive multiples of seven such that 3 times the first exceeds twice the third by 14. \n" ); document.write( "

Algebra.Com's Answer #239092 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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he general expression for consecutive multiples of seven is 7N, 7(N+1), 7(N+2), etc.
\n" ); document.write( "Find three consecutive multiples of seven such that 3 times the first exceeds
\n" ); document.write( " twice the third by 14.
\n" ); document.write( ":
\n" ); document.write( "3(7N) = 2(7(n+2) + 14
\n" ); document.write( "21N = 14(N+2) + 14
\n" ); document.write( "21N = 14N + 28 + 14
\n" ); document.write( "21N - 14n + 42
\n" ); document.write( "7N = 42, is the 1st multiple
\n" ); document.write( "then
\n" ); document.write( "42, 49, 56 are the 3 multiples \n" ); document.write( "

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