document.write( "Question 333541: The revenue achieved by selling x graphing calculators is figured to be
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document.write( "x(45-0.5x)dollars. The cost of each calculator is $25. How many graphing calculators must be sold to make a profit(revenue-cost) of at least 187.50? \n" );
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Algebra.Com's Answer #239082 by jrfrunner(365)![]() ![]() You can put this solution on YOUR website! let r=revenue \n" ); document.write( "let c=cost \n" ); document.write( "let p=profit \n" ); document.write( "let x=number of graphing calculators \n" ); document.write( "--- \n" ); document.write( "given \n" ); document.write( " \n" ); document.write( "c=25x \n" ); document.write( " \n" ); document.write( "simplify p: \n" ); document.write( "--- \n" ); document.write( "need to find x, such that p>187.50 \n" ); document.write( "== \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-- \n" ); document.write( "solve via quadratic solution for x \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=15 or 25 but you need to check for \"valid\" values \n" ); document.write( "--- \n" ); document.write( "draw a line \n" ); document.write( "mark the points 15 and 25 on this line \n" ); document.write( "you have created 3 number segments to check for validity of the x values \n" ); document.write( "1. x values from -infinity to 15 \n" ); document.write( "2. x values from 15 to 25 \n" ); document.write( "3. x values from 25 to + infinity \n" ); document.write( "-- \n" ); document.write( "choose a value from each segment, such as 0 for the first segment, 20 for the second segment, and 30 for the third segment. \n" ); document.write( "test these chosen x values against \n" ); document.write( "to determine the validity of each segment. \n" ); document.write( "-- \n" ); document.write( "you will find that the line segment for x between 15 to 25 that make the profit positive, and that is your answer (between 15 to 25 calculators will yield a proift greater than 187.50)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |