document.write( "Question 333537: I am feeling quite stupid when it comes to algebra and I again am having difficulties with another problem. I am asking for help and if at all possible explination on how to figure each step as i am attempting to understand the aspect of the problems. \r
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document.write( "the problem:
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document.write( "(x-2)/3+1=2x\r
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document.write( "any help will be much appreciated
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document.write( "thanks
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document.write( "becca \n" );
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Algebra.Com's Answer #239002 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! (x-2)/3+1=2x \n" ); document.write( "Subtract 1 \n" ); document.write( "(x-2)/3 = 2x - 1 \n" ); document.write( "Multiply by 3 \n" ); document.write( "x-2 = 3(2x - 1) \n" ); document.write( "x-2 = 6x - 3 \n" ); document.write( "Add 3 \n" ); document.write( "x + 1 = 6x \n" ); document.write( "Subtract x \n" ); document.write( "5x = 1 \n" ); document.write( "Divide by 5 \n" ); document.write( "x = 1/5 \n" ); document.write( " \n" ); document.write( " |