document.write( "Question 333537: I am feeling quite stupid when it comes to algebra and I again am having difficulties with another problem. I am asking for help and if at all possible explination on how to figure each step as i am attempting to understand the aspect of the problems. \r
\n" ); document.write( "\n" ); document.write( "the problem:
\n" ); document.write( "(x-2)/3+1=2x\r
\n" ); document.write( "\n" ); document.write( "any help will be much appreciated
\n" ); document.write( "thanks
\n" ); document.write( "becca
\n" ); document.write( "

Algebra.Com's Answer #239002 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
(x-2)/3+1=2x
\n" ); document.write( "Subtract 1
\n" ); document.write( "(x-2)/3 = 2x - 1
\n" ); document.write( "Multiply by 3
\n" ); document.write( "x-2 = 3(2x - 1)
\n" ); document.write( "x-2 = 6x - 3
\n" ); document.write( "Add 3
\n" ); document.write( "x + 1 = 6x
\n" ); document.write( "Subtract x
\n" ); document.write( "5x = 1
\n" ); document.write( "Divide by 5
\n" ); document.write( "x = 1/5
\n" ); document.write( "
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