document.write( "Question 333513: Log2 x+log2(x-3)=2 \n" ); document.write( "
Algebra.Com's Answer #238983 by benazir.sj@gmail.com(109)\"\" \"About 
You can put this solution on YOUR website!
Log2 x+log2(x-3)=2\r
\n" ); document.write( "\n" ); document.write( "property of log
\n" ); document.write( "log a + log b = log a*b
\n" ); document.write( " and 2 is the base\r
\n" ); document.write( "\n" ); document.write( "log2[x*(x-3)]=2
\n" ); document.write( "log[x*(x-3)=2^2
\n" ); document.write( "x(x-3)=4
\n" ); document.write( "x^2 -3x =4
\n" ); document.write( "x^2-3x-4=0
\n" ); document.write( "x^2-4x+x-4=0
\n" ); document.write( "x(x-4)+1(x-4)=0
\n" ); document.write( "(x+1)(x-4)=0
\n" ); document.write( "x=-1 or x=4\r
\n" ); document.write( "\n" ); document.write( "x= -1,4 \n" ); document.write( "
\n" );