document.write( "Question 333504: Hi; I was hoping someone could help me with this problem.\r
\n" ); document.write( "\n" ); document.write( "Maximum area. Jason plans to fence a rectangular area with 100 meters of fencing. He has written the formula A = w(50 - w) to express the area in terms of the width w. What is the maximum possible area that he can enclose with his fencing?\r
\n" ); document.write( "\n" ); document.write( "Just by \"guessing\" I come up with a width of 25m and a length of 25 meters. How do I figure area? The answer in the back of the book says it's 625 meters, but I don't know how they got this. \r
\n" ); document.write( "\n" ); document.write( "Help please?!??\r
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Algebra.Com's Answer #238973 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Jason plans to fence a rectangular area with 100 meters of fencing. He has written the formula A = w(50 - w) to express the area in terms of the width w. What is the maximum possible area that he can enclose with his fencing?
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\n" ); document.write( "A = w(50-w)
\n" ); document.write( "A = 50w-w^2
\n" ); document.write( "-w^2++50w
\n" ); document.write( "a = -1 ; b = 50
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\n" ); document.write( "Maximum area occurs when w = -b/2a = -50/(2*-1) = 25
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\n" ); document.write( "Then 50-w = 25
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\n" ); document.write( "Maximum area = 25*25 = 625 sq meters
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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