document.write( "Question 333505: application of linear equations\r
\n" ); document.write( "\n" ); document.write( "Andrew invested a total of Php18,000, part at 5% and part at 9%. If his income for one year from the 9% investment was Php100 less than his income from the 5% investment, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #238972 by mananth(16946)\"\" \"About 
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Andrew invested a total of 18,000,
\n" ); document.write( "part at 5% . Let this investment be x
\n" ); document.write( "interest = 0.05x
\n" ); document.write( "..
\n" ); document.write( "part at 9%. this will be 18000-x
\n" ); document.write( "interest will be (18000-x )*0.09
\n" ); document.write( "..
\n" ); document.write( "interest from the 9% investment was Php100 less than his income from the 5%
\n" ); document.write( "..
\n" ); document.write( "income from 5% - income from 9% = 100
\n" ); document.write( "..
\n" ); document.write( "0.05x - 0.09(18000-x)= 100
\n" ); document.write( "0.05x-1620+0.09x=100
\n" ); document.write( "0.14x=1620+100
\n" ); document.write( "0.14x=1720
\n" ); document.write( "x= 1720/0.14
\n" ); document.write( "= Php 12,286
\n" ); document.write( "..
\n" ); document.write( "investment at 9% will be 18000-12286
\n" ); document.write( "= Php 5,714
\n" ); document.write( "CHECK(0.05*12286) - 0.09(18000-12286)=100\r
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