document.write( "Question 333482: The product of two consecutive integers is 4 less than four times their sum. Find the integers.I had tried to solve it but it made me just get more confused with the whole question. \n" ); document.write( "
Algebra.Com's Answer #238959 by jrfrunner(365)\"\" \"About 
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A. two consecutive integers : x and x+1\r
\n" ); document.write( "\n" ); document.write( "B. The product of two consecutive integers x*(x+1)
\n" ); document.write( "C. 4 less than four times their sum: 4[x+(x+1)]-4
\n" ); document.write( "D. x*(x+1)=4[x+(x+1)]-4 (equate the sides)
\n" ); document.write( "E. x^2+x=4(2x+1)-4 (simplify the equation)
\n" ); document.write( "F. x^2 +x=8x+4-4=8x (simplify the equation)
\n" ); document.write( "G. x^2=-x+8x=7x (subtract x from both sides)
\n" ); document.write( "H. x=7 (divide both sides by x)
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\n" ); document.write( "check solution by substituting x=7 back in original equation
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\n" ); document.write( "x*(x+1)=4[x+(x+1)]-4
\n" ); document.write( "7*(7+1)=4*(7+(7+1))-4
\n" ); document.write( "7*8=4*(15)-4
\n" ); document.write( "56=60-4=56
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