document.write( "Question 333433: One interger is 3 more than twice another. If the product of those integers is 65. find the two integers \n" ); document.write( "
Algebra.Com's Answer #238922 by ankor@dixie-net.com(22740)\"\" \"About 
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Two integers, x & y
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\n" ); document.write( "\"One integer is 3 more than twice another.\"
\n" ); document.write( "x = 2y + 3
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\n" ); document.write( "\"If the product of those integers is 65.\"
\n" ); document.write( "x * y = 65
\n" ); document.write( "we can also write this:
\n" ); document.write( "x = \"65%2Fy\"
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\n" ); document.write( "replace x in the 1st equation with \"65%2Fy\"
\n" ); document.write( "\"65%2Fy\" = 2y + 3
\n" ); document.write( "Multiply both sides by y
\n" ); document.write( "65 = 2y^2 + 3y
\n" ); document.write( "a quadratic equation
\n" ); document.write( "2y^2 + 3y - 65 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(2y + 13)(y - 5) = 0
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\n" ); document.write( "The integer solution:
\n" ); document.write( "y = 5 is one integer
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\n" ); document.write( "find x using the 1st equation:
\n" ); document.write( "x = 2(5) + 3
\n" ); document.write( "x = 13 is the other integer
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\n" ); document.write( "Check 5 * 13 = 65\r
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