document.write( "Question 333318: After sampling from two binomial populations, we found the following:\r
\n" ); document.write( "\n" ); document.write( "p = 0.48 n1 = 100 p2 = 0.052 n2 =100\r
\n" ); document.write( "\n" ); document.write( "if we estimate with 90% confidence the difference in population proportions, what would be the outome?
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Algebra.Com's Answer #238879 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
you can apply the binomial method directly which can be tedious and difficult
\n" ); document.write( "or \"if\" the assumptions are met, can apply a normal approximation to the binomial.
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\n" ); document.write( "\n" ); document.write( "The enable the use of the normal approximation, the following need to be met
\n" ); document.write( "1. \"n%5B1%5D%2Ap%5B1%5D%3E5\" and \"n%5B2%5D%2Ap%5B2%5D%3E5\" and \"n%5B1%5D%2A%281-p%5B1%5D%29%3E5\" and \"n%5B2%5D%2A%281-p%5B2%5D%29%3E5\"
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\n" ); document.write( "you provided p1 = 0.48 n1 = 100 p2 = 0.052 n2 =100
\n" ); document.write( "NOTE: not sure if your p2 is correct. Nevertheless, it looks like the requirements above are met.
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\n" ); document.write( "90% confidence interval for difference in the population proportions yields Z=1.645
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\n" ); document.write( "Upper confidence interval value:
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\n" ); document.write( "confidence interval = \"%280.48-0.052%29-1.645%2Asqrt%280.48%2A0.52%2F100%2B0.052%2A0.948%2F100%29\" to \"%280.48-0.052%29%2B1.645%2Asqrt%280.48%2A0.52%2F100%2B0.052%2A0.948%2F100%29\"
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\n" ); document.write( "you can do the math
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