document.write( "Question 333357: There is a circle with a 16 inch chord. The midpoint of the chord is 6 inches from the center of the circle. What is the length of the radius of the circle? \n" ); document.write( "

Algebra.Com's Answer #238874 by biggstry(3) $\"\"$ $\"About$

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CONSTRUCTION: Draw a circle of any size,draw a chord AB to cut the circle.Draw a perpendicular line from centre O of the circle to bisect the chord at C.DESCRIPTION: This will form an isosceles triangle OAB which comprises of two right angle triangle AOC and BOC. From the question,OC=6inches, AB=16inches, AC=CB=8inches.let r be the lenght of the radius{the length between centre O and the locus point A $ C) therefore,Applying pythagoras theorem to triangle AOC. r^2=AO=OB=OC^2+AC^2 ;r^2=6^2+8^2; r^2=100; r=10inches.hence, the lenth of the radius of the circle is 10inches \n" ); document.write( "

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