document.write( "Question 333345: A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration? \n" ); document.write( "
Algebra.Com's Answer #238853 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration?
\n" ); document.write( "---------------
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 10L
\n" ); document.write( "Quality: 0.35x + 0.50y = 0.40*10
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Multiply thru 1st by 25
\n" ); document.write( "Multiply thru 2nd by 100
\n" ); document.write( "-------------------------------
\n" ); document.write( "Quantity: 35x + 35y = 35*10
\n" ); document.write( "Quality: 35x + 50y = 40*10
\n" ); document.write( "---------------------------------
\n" ); document.write( "Subtract Quantity from Quality to get:
\n" ); document.write( "15y = 5*10
\n" ); document.write( "y = 3 1/3 L (amt of 50% NaCl needed in the mixture)
\n" ); document.write( "---
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x = 10- 3 1/3 = 6 2/3 L (amt of 35% NaCl needed in the mixture)
\n" ); document.write( "===============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
\n" );