document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=333220>Question 333220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complimentary The sum of the measure of the first angle and one-fourth the second angle is 88.50. Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #238837 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=238837\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let one angle be x<BR>\n" );
document.write( "the other will be 90-x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x+1/4(90-x)=88.5<BR>\n" );
document.write( "4x+90-x / 4 =88.5<BR>\n" );
document.write( "3x+90=4*88.5<BR>\n" );
document.write( "3x+90=354<BR>\n" );
document.write( "3x=354-90<BR>\n" );
document.write( "3x=264<BR>\n" );
document.write( "x=264/3<BR>\n" );
document.write( "x=88 deg<BR>\n" );
document.write( "the other angle = 2 deg </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );